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Popular >

y^'-2e^xy=-2e^x

Solution

y^{^{'}} - 2 e^{x} y = - 2 e^{x}

Solution

y = - e^{2 e^{x} + c_{1}} + 1

Solution steps

y^{'} (x) - 2 e^{x} y = - 2 e^{x}

Solve separable ODE:

y = - e^{2 e^{x} + c_{1}} + 1

y = - e^{2 e^{x} + c_{1}} + 1

Graph

Popular Examples

f(x)=3sin(5x)f^'(x)((4pi))/(15)

f (x) = 3 sin (5 x) f^{^{'}} (x) \frac{( 4 π )}{15}

y^'=(x(x^2+1))/((4y^2))

y^{^{'}} = \frac{x ( x ^{2} + 1 )}{( 4 y ^{2} )}

y^'=(x^2)/(y^2),y(1)=1

y^{^{'}} = \frac{x ^{2}}{y ^{2}}, y (1) = 1

(dx)/(dt)=(100-x)/(10)

\frac{d x}{d t} = \frac{100 - x}{10}

((df)/(dy))f(y)=e^{-y}

(\frac{df}{d y}) f (y) = e^{- y}

Frequently Asked Questions (FAQ)

What is the solution for y^'-2e^xy=-2e^x ?
The solution for y^'-2e^xy=-2e^x is y=-e^{2e^x+c_{1}}+1