What is the solution for y^'=((4t))/y ?

The solution for y^'=((4t))/y is y=sqrt(4t^2+c_{1)},y=-sqrt(4t^2+c_{1)}

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y^'=((4t))/y

y^{^{'}} = \frac{( 4 t )}{y}

y = 4 t^{2} + c_{1}, y = - 4 t^{2} + c_{1}

Solution steps

y^{'} (t) = \frac{( 4 t )}{y}

Solve separable ODE:

y = 4 t^{2} + c_{1}, y = - 4 t^{2} + c_{1}

y = 4 t^{2} + c_{1}, y = - 4 t^{2} + c_{1}

y^{^{'}} = - \frac{x}{( y - 3 )}

\frac{d y}{d t} = k y^{2}

y^{^{'}} = k (\frac{x ^{1.4}}{2.4}) (y - 100)

\frac{d y}{d x} = \frac{x ^{2}}{1 + y ^{2}}, y (2) = 1

5 x y d x + 3 y^{2} d y = 0

What is the solution for y^'=((4t))/y ?
The solution for y^'=((4t))/y is y=sqrt(4t^2+c_{1)},y=-sqrt(4t^2+c_{1)}