What is the solution for (2dy)/y =(2cos(2x))/(sin(2x))dx ?

The solution for (2dy)/y =(2cos(2x))/(sin(2x))dx is y=c_{1}sqrt(sin(2x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2dy)/y =(2cos(2x))/(sin(2x))dx

\frac{2 d y}{y} = \frac{2 cos ( 2 x )}{sin ( 2 x )} d x

y = c_{1} sin (2 x)

Solution steps

\frac{2 d y}{y} = \frac{2 cos ( 2 x )}{sin ( 2 x )} d x

Solve separable ODE:

y = c_{1} sin (2 x)

y = c_{1} sin (2 x)

\frac{d v}{d t} = 9.81 - 10 v, v (0) = 0

y^{3} \frac{d y}{d x} = 2 x^{4} y^{4} - 4 x^{4}

x^{3} \frac{d y}{d x} - sin (x) y = 0

y^{^{'}} = \frac{x ^{2} - 3}{y ^{2}}, y (0) = 4

y^{^{'}} = \frac{x ^{2} - 3}{y ^{2}}, y (0) = 6

What is the solution for (2dy)/y =(2cos(2x))/(sin(2x))dx ?
The solution for (2dy)/y =(2cos(2x))/(sin(2x))dx is y=c_{1}sqrt(sin(2x))