What is the solution for (dy)/(dx)y=ln(7)x^2 ?

The solution for (dy)/(dx)y=ln(7)x^2 is y=sqrt((2ln(7)x^3+c_{1))/3},y=-sqrt((2ln(7)x^3+c_{1))/3}

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(dy)/(dx)y=ln(7)x^2

\frac{d y}{d x} y = ln (7) x^{2}

y = \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}, y = - \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}

Solution steps

\frac{d y}{d x} y = ln (7) x^{2}

Solve separable ODE:

y = \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}, y = - \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}

y = \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}, y = - \frac{2 ln ( 7 ) x ^{3} + c _{1}}{3}

\frac{d y}{d x} = (x - 5) e^{- 2 y}, y (2) = ln (5)

\frac{d y}{d x} = x^{2} + x^{2} y^{2}

\frac{d y}{d x} + 4 y = 3, y (0) = 0

\frac{d y}{d x} = y^{2} - 6

\frac{d y}{d x} = \frac{x ( y - 4 ) + y - 4}{x ( y - 6 ) - 3 ( y - 6 )}

What is the solution for (dy)/(dx)y=ln(7)x^2 ?
The solution for (dy)/(dx)y=ln(7)x^2 is y=sqrt((2ln(7)x^3+c_{1))/3},y=-sqrt((2ln(7)x^3+c_{1))/3}