What is the tangent of y= 2/(x-6),(8,1) ?

The tangent of y= 2/(x-6),(8,1) is y=-1/2 x+5

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tangent of y= 2/(x-6),(8,1)

tangent of

y = \frac{2}{x - 6}, (8, 1)

y = - \frac{1}{2} x + 5

Solution steps

Find the slope of

y = \frac{2}{x - 6} : \frac{d y}{d x} = - \frac{2}{( x - 6 ) ^{2}}

Compute the slope of

y = \frac{2}{x - 6}

(8, 1) : m = - \frac{1}{2}

Find the line with slope m=

- \frac{1}{2}

and passing through

(8, 1) : y = - \frac{1}{2} x + 5

y = - \frac{1}{2} x + 5

5 x - 6 y (x^{2} + 1) \frac{d y}{d x} = 0

2 y y^{^{'}} + 2 = y^{2} + 2 x, y (0) = 7

\int 16 arctan (x) d x

\frac{d}{d x} (x^{2}, x + 2 x cos (x) - 2 sec (x))

\frac{d}{d x} (ln (2 cos (x)))

What is the tangent of y= 2/(x-6),(8,1) ?
The tangent of y= 2/(x-6),(8,1) is y=-1/2 x+5