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Popular >

y^'=(1/(1+x))y

Solution

y^{^{'}} = (\frac{1}{1 + x}) y

Solution

y = e^{c_{1}} + e^{c_{1}} x

Solution steps

y^{'} (x) = (\frac{1}{1 + x}) y

Solve separable ODE:

y = e^{c_{1}} + e^{c_{1}} x

y = e^{c_{1}} + e^{c_{1}} x

Graph

Popular Examples

y=(\sqrt[3]{(1+3x^2)^2})/x (dy)/(dx)

y = \frac{3 ( 1 + 3 x ^{2} ) ^{2}}{x} \frac{d y}{d x}

(dy)/(dt)y=sqrt(3+csc(t^6))

\frac{d y}{d t} y = 3 + csc (t^{6})

6x-4ysqrt(x^2+1)(dy)/(dx)=0,y(0)=-5

6 x - 4 y x^{2} + 1 \frac{d y}{d x} = 0, y (0) = - 5

6 u z^{2} d u = u d z

y^'=4y+b,y(0)=1

y^{^{'}} = 4 y + b, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for y^'=(1/(1+x))y ?
The solution for y^'=(1/(1+x))y is y=e^{c_{1}}+e^{c_{1}}x