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Popular >

x= y/(y^'+y)

Solution

x = \frac{y}{y ^{^{'}} + y}

Solution

y = e^{- x + c_{1}} x

Solution steps

x = \frac{y}{y ^{'} ( x ) + y}

Solve separable ODE:

y = e^{- x + c_{1}} x

y = e^{- x + c_{1}} x

Graph

Popular Examples

20((dv)/(dt))=-(20)(32)-0.0025v

20 (\frac{d v}{d t}) = - (20) (32) - 0.0025 v

(dy)/(dx)*(1+e^x)=e^{x-y}

\frac{d y}{d x} \cdot (1 + e^{x}) = e^{x - y}

y^'=-9.8-(0.0025)/4 y

y^{^{'}} = - 9.8 - \frac{0.0025}{4} y

y^{^{'}} = y tan (x)

(dx)/(dt)=te^x,x=1

\frac{d x}{d t} = t e^{x}, x = 1

Frequently Asked Questions (FAQ)

What is the solution for x= y/(y^'+y) ?
The solution for x= y/(y^'+y) is y=e^{-x+c_{1}}x