What is the solution for y^'-x^5y^4=0,y(0)=2,y(2)=a ?

The solution for y^'-x^5y^4=0,y(0)=2,y(2)=a is y=-2/(\sqrt[3]{4x^6-1)}

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y^'-x^5y^4=0,y(0)=2,y(2)=a

y^{^{'}} - x^{5} y^{4} = 0, y (0) = 2, y (2) = a

y = - \frac{2}{3 4 x ^{6} - 1}

Solution steps

y^{'} (x) - x^{5} y^{4} = 0

Solve separable ODE:

y = - \frac{2}{3 4 x ^{6} - 1}

y = - \frac{2}{3 4 x ^{6} - 1}

2 y^{^{'}} - y y^{^{'}} = x^{2} + 1

\frac{2 d y}{d t} + 4 y = 6, y (0) = 1 (\frac{1}{2})

\frac{d y}{d x} = (2 - y) sin (x), x = 2, c^{1} = 3

x^{^{'}} + 2^{2} \cdot 3^{2} \cdot x = 0

y^{2} \frac{d y}{d x} - 2 x e^{x^{2} + 1} = 0

What is the solution for y^'-x^5y^4=0,y(0)=2,y(2)=a ?
The solution for y^'-x^5y^4=0,y(0)=2,y(2)=a is y=-2/(\sqrt[3]{4x^6-1)}