What is the solution for (dy)/(dx)+y=y^{-2} ?

The solution for (dy)/(dx)+y=y^{-2} is y=\sqrt[3]{-e^{-3x-c_{1}}+1}

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(dy)/(dx)+y=y^{-2}

\frac{d y}{d x} + y = y^{- 2}

y = 3 - e^{- 3 x - c_{1}} + 1

Solution steps

\frac{d y}{d x} + y = y^{- 2}

Solve separable ODE:

y = 3 - e^{- 3 x - c_{1}} + 1

y = 3 - e^{- 3 x - c_{1}} + 1

2 d y - (y - 7)^{2} d x = 0

\frac{d}{d x} (y^{3}) = 50 x

\frac{d y}{d x} = \frac{1}{y - 2}

\frac{\frac{d y}{d t}}{y} = \frac{( 2 t + 1 )}{t ^{2}}

\frac{x y ^{^{'}}}{y} = 2

What is the solution for (dy)/(dx)+y=y^{-2} ?
The solution for (dy)/(dx)+y=y^{-2} is y=\sqrt[3]{-e^{-3x-c_{1}}+1}