What is the solution for y^'=18\sqrt[4]{xy} ?

The solution for y^'=18\sqrt[4]{xy} is

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y^'=18\sqrt[4]{xy}

y^{^{'}} = 18 4 x y

y = \frac{3 2176782336 x ^{5} + 604661760 c _{1} x ^{\frac{15}{4}} + 62985600 c _{1}^{2} x ^{\frac{5}{2}} + 2916000 c _{1}^{3} x ^{\frac{5}{4}} + 50625 c _{1}^{4}}{20 3 20}

Solution steps

y^{'} (x) = 18 4 x y

Solve separable ODE:

y = \frac{3 2176782336 x ^{5} + 604661760 c _{1} x ^{\frac{15}{4}} + 62985600 c _{1}^{2} x ^{\frac{5}{2}} + 2916000 c _{1}^{3} x ^{\frac{5}{4}} + 50625 c _{1}^{4}}{20 3 20}

y = \frac{3 2176782336 x ^{5} + 604661760 c _{1} x ^{\frac{15}{4}} + 62985600 c _{1}^{2} x ^{\frac{5}{2}} + 2916000 c _{1}^{3} x ^{\frac{5}{4}} + 50625 c _{1}^{4}}{20 3 20}

y^{^{'}} + (x - 10) y^{^{'}} + y = 0

\frac{d ^{2} x}{d x ^{2}} + a \cdot \frac{d y}{d x} = b \cdot y^{- 2}

\frac{d p}{d y} \cdot p = - \frac{1}{2 y ^{3}}

y^{^{'}} = e^{(2 + 3) x + (1 + 1) y}

\frac{d y}{d x} = 2 (cos (x)) y

What is the solution for y^'=18\sqrt[4]{xy} ?
The solution for y^'=18\sqrt[4]{xy} is