What is the solution for -(dh)/(dt)=5sqrt(h) ?

The solution for -(dh)/(dt)=5sqrt(h) is h=(25t^2)/4-(5c_{1}t)/2+(c_{1}^2)/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

-(dh)/(dt)=5sqrt(h)

- \frac{d h}{d t} = 5 h

h = \frac{25 t ^{2}}{4} - \frac{5 c _{1} t}{2} + \frac{c _{1}^{2}}{4}

Solution steps

- \frac{d h}{d t} = 5 h

Solve separable ODE:

h = \frac{25 t ^{2}}{4} - \frac{5 c _{1} t}{2} + \frac{c _{1}^{2}}{4}

h = \frac{25 t ^{2}}{4} - \frac{5 c _{1} t}{2} + \frac{c _{1}^{2}}{4}

ln (x) y^{^{'}} - \frac{2 y}{x} = 0

3 e^{7 x} \frac{d y}{d x} = - 49 \frac{x}{y ^{2}}, y (0) = 1

a y d x + x d y = 0

y^{^{'}} 2 y = 3 e^{4 x} - 4 sin (4 x), y (0) = - 5

3 y \cdot d x - x \cdot d y = 0

What is the solution for -(dh)/(dt)=5sqrt(h) ?
The solution for -(dh)/(dt)=5sqrt(h) is h=(25t^2)/4-(5c_{1}t)/2+(c_{1}^2)/4