What is area y=-x,y=-8x+13,[0, 13/8 ] ?

The answer to area y=-x,y=-8x+13,[0, 13/8 ] is 1521/128

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area y=-x,y=-8x+13,[0, 13/8 ]

area

y = - x, y = - 8 x + 13, [0, \frac{13}{8}]

\frac{1521}{128}

Decimal Notation

11.8828125

Solution steps

Apply the area formula:

\int_{0}^{\frac{13}{8}} ∣ - 7 x + 13 ∣ d x

Solve

\int_{0}^{\frac{13}{8}} ∣ - 7 x + 13 ∣ d x : \frac{1521}{128}

The area is:

= \frac{1521}{128}

(2 x + 1) \frac{d y}{d x} = 4

\int \frac{1}{4 + 5 x ^{6}} (30 x^{5}) d x

x (2 x + 7)^{\frac{1}{3}}

t^{2} y^{^{''}} + 6 t y^{^{'}} - 6 y = 0

\frac{\partial}{\partial x} ((x^{3} - y^{2})^{(- 1)})

What is area y=-x,y=-8x+13,[0, 13/8 ] ?
The answer to area y=-x,y=-8x+13,[0, 13/8 ] is 1521/128