What is the solution for y^'=0.01398y,y(0)=150 ?

The solution for y^'=0.01398y,y(0)=150 is y=150e^{0.01398t}

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y^'=0.01398y,y(0)=150

y^{^{'}} = 0.01398 y, y (0) = 150

y = 150 e^{0.01398 t}

Solution steps

y^{'} (t) = 0.01398 y

Solve separable ODE:

y = 150 e^{0.01398 t}

y = 150 e^{0.01398 t}

\frac{d y}{d x} = (- 2 x + 1) y, y (0) = 6.8

\frac{d y}{d x} + y = y (sin (x) + 1)

3 x y^{2} y^{^{'}} = y^{3}

\frac{d N}{d t} = r N (t) (1 - \frac{N}{2})

\frac{d x}{d y} = \frac{- 1}{x ^{2} y ^{2}}

What is the solution for y^'=0.01398y,y(0)=150 ?
The solution for y^'=0.01398y,y(0)=150 is y=150e^{0.01398t}