What is the solution for (dy)/(dx)= 1/(sqrt(y)) ?

The solution for (dy)/(dx)= 1/(sqrt(y)) is y=\sqrt[3]{(9x^2)/4+(9c_{1}x)/2+(9c_{1}^2)/4}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)= 1/(sqrt(y))

\frac{d y}{d x} = \frac{1}{y}

y = 3 \frac{9 x ^{2}}{4} + \frac{9 c _{1} x}{2} + \frac{9 c _{1}^{2}}{4}

Solution steps

\frac{d y}{d x} = \frac{1}{y}

Solve separable ODE:

y = 3 \frac{9 x ^{2}}{4} + \frac{9 c _{1} x}{2} + \frac{9 c _{1}^{2}}{4}

y = 3 \frac{9 x ^{2}}{4} + \frac{9 c _{1} x}{2} + \frac{9 c _{1}^{2}}{4}

\frac{d}{d x} (sin (x) - cos (y) - 2) = 0

y^{^{'}} - 0.1 x y = x

\frac{d y}{d x} = \frac{15 x ^{2} - 6 x + 2}{( y + 2 )}

\frac{d y}{d x} = \frac{1 + x}{x y ^{6}}, y (1) = 5

\frac{d y}{d x} = 3 x^{2} + 3 x^{2} y^{2}

What is the solution for (dy)/(dx)= 1/(sqrt(y)) ?
The solution for (dy)/(dx)= 1/(sqrt(y)) is y=\sqrt[3]{(9x^2)/4+(9c_{1}x)/2+(9c_{1}^2)/4}