What is the solution for dy=((y+4))/(x+5)dx ?

The solution for dy=((y+4))/(x+5)dx is y=e^{c_{1}}x+5e^{c_{1}}-4

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dy=((y+4))/(x+5)dx

d y = \frac{( y + 4 )}{x + 5} d x

y = e^{c_{1}} x + 5 e^{c_{1}} - 4

Solution steps

d y = \frac{( y + 4 )}{x + 5} d x

Solve separable ODE:

y = e^{c_{1}} x + 5 e^{c_{1}} - 4

y = e^{c_{1}} x + 5 e^{c_{1}} - 4

\frac{d y}{d x} y = \frac{1 - 2 x ^{2}}{x ^{4} - 2 x ^{2} + 6}

y d x + (\frac{x - 1}{2 x ^{3} y}) d y = 0

\frac{d y}{d x} 3 x^{2} - 3 y^{2} = 4

x^{^{'}} = \frac{( 6 - x )}{300 + t}

\frac{d y}{d x} = 10 e^{2 x - y}, y (0) = 0

What is the solution for dy=((y+4))/(x+5)dx ?
The solution for dy=((y+4))/(x+5)dx is y=e^{c_{1}}x+5e^{c_{1}}-4