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Popular >

x^'=-x-2

Solution

x^{^{'}} = - x - 2

Solution

x = e^{- t - c_{1}} - 2

Solution steps

x^{'} (t) = - x - 2

Solve separable ODE:

x = e^{- t - c_{1}} - 2

x = e^{- t - c_{1}} - 2

Graph

Popular Examples

(4+5t)y^'+5y=-1

(4 + 5 t) y^{^{'}} + 5 y = - 1

y^'=x^4*y^{-1},y(0)=7

y^{^{'}} = x^{4} \cdot y^{- 1}, y (0) = 7

(cos(θ))dx+(1+e-x)(sin(θ))dθ=0

(cos (θ)) d x + (1 + e - x) (sin (θ)) d θ = 0

(dr)/(dq)=(50-4q)e^{-r/5}

\frac{d r}{d q} = (50 - 4 q) e^{- \frac{r}{5}}

(dr(θ))/(r(θ)^2)=(r(θ)dθ)/(θ^2)

\frac{d r ( θ )}{r ( θ ) ^{2}} = \frac{r ( θ ) d θ}{θ ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for x^'=-x-2 ?
The solution for x^'=-x-2 is x=e^{-t-c_{1}}-2