What is the solution for (dy)/(dx)y=23^x ?

The solution for (dy)/(dx)y=23^x is y=sqrt((2*23^x+c_{1))/(ln(23))},y=-sqrt((2*23^x+c_{1))/(ln(23))}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)y=23^x

\frac{d y}{d x} y = 2 3^{x}

y = \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}, y = - \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}

Solution steps

\frac{d y}{d x} y = 2 3^{x}

Solve separable ODE:

y = \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}, y = - \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}

y = \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}, y = - \frac{2 \cdot 2 3 ^{x} + c _{1}}{ln ( 23 )}

x^{^{'}} + 0.09 \cdot x = 0, x (0) = 1

(x^{2} + 2 x - 1) y^{^{'}} - (x - 1) y = x - 1

y^{2} \frac{d y}{d x} = x^{2}

\frac{d x}{d t} = 50 - \frac{7 x}{100}

\frac{d y}{d x} = y (2 x^{2} + 3)

What is the solution for (dy)/(dx)y=23^x ?
The solution for (dy)/(dx)y=23^x is y=sqrt((2*23^x+c_{1))/(ln(23))},y=-sqrt((2*23^x+c_{1))/(ln(23))}