What is the solution for (dx)/(dt)=x^2+(1/81) ?

The solution for (dx)/(dt)=x^2+(1/81) is x=(tan((t+c_{1})/9))/(9)

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(dx)/(dt)=x^2+(1/81)

\frac{d x}{d t} = x^{2} + (\frac{1}{81})

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

Solution steps

\frac{d x}{d t} = x^{2} + (\frac{1}{81})

Solve separable ODE:

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

x = \frac{tan ( \frac{t + c _{1}}{9} )}{9}

2 y^{^{'}} - 4 e^{2 x} y = 0, y (0) = 6

e^{x} y^{^{'}} - e^{x} \cdot y = e^{x}

\frac{d y}{d x} = 3 y e^{x}

\frac{d}{d x} (x - y^{10}) = \frac{d}{d x} (8)

\frac{d y}{d x} y = \frac{2 x + 3}{x + 1}

What is the solution for (dx)/(dt)=x^2+(1/81) ?
The solution for (dx)/(dt)=x^2+(1/81) is x=(tan((t+c_{1})/9))/(9)