What is the solution for (-y-2)dx+(x-2)dy=0 ?

The solution for (-y-2)dx+(x-2)dy=0 is y=e^{c_{1}}x-2e^{c_{1}}-2

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(-y-2)dx+(x-2)dy=0

(- y - 2) d x + (x - 2) d y = 0

y = e^{c_{1}} x - 2 e^{c_{1}} - 2

Solution steps

(- y - 2) d x + (x - 2) d y = 0

Solve separable ODE:

y = e^{c_{1}} x - 2 e^{c_{1}} - 2

y = e^{c_{1}} x - 2 e^{c_{1}} - 2

\frac{d x}{d t} x = t^{2} - 5

\frac{d y}{d t} = 100 - y, y (0) = 20

\frac{d x}{d t} = 30 - 11 x + x^{2}

\frac{d}{d x} (x y) = \frac{d}{d x} (x + y)

\frac{d}{d x} ((x) y) = (y) x

What is the solution for (-y-2)dx+(x-2)dy=0 ?
The solution for (-y-2)dx+(x-2)dy=0 is y=e^{c_{1}}x-2e^{c_{1}}-2