en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'= 1/3 y

Solution

y^{^{'}} = \frac{1}{3} y

Solution

y = e^{\frac{t + c _{1}}{3}}

Solution steps

y^{'} (t) = \frac{1}{3} y

Solve separable ODE:

y = e^{\frac{t + c _{1}}{3}}

y = e^{\frac{t + c _{1}}{3}}

Graph

Popular Examples

(dy)/(dx)y=u^2-2u,u= 1/(x^2)

\frac{d y}{d x} y = u^{2} - 2 u, u = \frac{1}{x ^{2}}

3= pi/(12) d/(dt)((h(t))^3)

3 = \frac{π}{12} \frac{d}{d t} ((h (t))^{3})

2sin(3x)sin(2y)dy=3cos(3x)cos(2y)dx

2 sin (3 x) sin (2 y) d y = 3 cos (3 x) cos (2 y) d x

7sqrt(xy)(dy)/(dx)=3,y>0,x>0

7 x y \frac{d y}{d x} = 3, y > 0, x > 0

(dx)/(dt)+(8x)/(240)=2

\frac{d x}{d t} + \frac{8 x}{240} = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'= 1/3 y ?
The solution for y^'= 1/3 y is y=e^{(t+c_{1})/3}