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Popular >

y^'+x/(x^2-9)*y=0

Solution

y^{^{'}} + \frac{x}{x ^{2} - 9} \cdot y = 0

Solution

y = \frac{c _{1}}{x ^{2} - 9}

Solution steps

y^{'} (x) + \frac{x}{x ^{2} - 9} \cdot y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2} - 9}

y = \frac{c _{1}}{x ^{2} - 9}

Graph

Popular Examples

(dx)/(dt)=10-x/(10)

\frac{d x}{d t} = 10 - \frac{x}{10}

y^3((dy)/(dx))=2x^2y^4-6x^2

y^{3} (\frac{d y}{d x}) = 2 x^{2} y^{4} - 6 x^{2}

y^'= y/(x+xe^x)

y^{^{'}} = \frac{y}{x + x e ^{x}}

(t^2+1)dy+3tydt=6tdt,y(0)=5

(t^{2} + 1) d y + 3 t y d t = 6 t d t, y (0) = 5

(dx)/(dy)=((x^2y^2)/((x+1)))

\frac{d x}{d y} = (\frac{x ^{2} y ^{2}}{( x + 1 )})

Frequently Asked Questions (FAQ)

What is the solution for y^'+x/(x^2-9)*y=0 ?
The solution for y^'+x/(x^2-9)*y=0 is y=(c_{1})/(sqrt(x^2-9))