What is the solution for y(dy)/(dx)=2x(y+1) ?

The solution for y(dy)/(dx)=2x(y+1) is y=-\W(-1/(e^{-c_{1)+x^2}})-1

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y(dy)/(dx)=2x(y+1)

y \frac{d y}{d x} = 2 x (y + 1)

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

Solution steps

y \frac{d y}{d x} = 2 x (y + 1)

Solve Bernoulli ODE:

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

y = - W (- \frac{1}{e ^{- c_{1} + x^{2}}}) - 1

\frac{( t ^{2} )}{x} d t = d x

\frac{d y}{d x} y = \frac{4 sin ( x )}{9 - 8 sin ( x )}

\frac{d y}{d t} = - k (y - 24)

2 x y^{^{'}} - y^{3} = 0

\frac{d y}{d x} y = - 3 x^{7} + \frac{3}{5} x^{4} + 568 x + 12

What is the solution for y(dy)/(dx)=2x(y+1) ?
The solution for y(dy)/(dx)=2x(y+1) is y=-\W(-1/(e^{-c_{1)+x^2}})-1