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Popular >

y^'=x+xy+1+y

Solution

y^{^{'}} = x + x y + 1 + y

Solution

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Solution steps

y^{'} (x) = x + x y + 1 + y

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} + x + c_{1}} - 1

Graph

Popular Examples

(dy)/(dx)=(9+17x)/(xy^2),x>0,y(1)=2

\frac{d y}{d x} = \frac{9 + 17 x}{x y ^{2}}, x > 0, y (1) = 2

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(1 + y^{2}) d x - y (x + x^{3}) d y = 0

(dy)/(dx)= 4/(y^2)x

\frac{d y}{d x} = \frac{4}{y ^{2}} x

xdx=x^2e^{\H(x)}d\H(x)

x d x = x^{2} e^{H (x)} d H (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=x+xy+1+y ?
The solution for y^'=x+xy+1+y is y=e^{(x^2)/2+x+c_{1}}-1