What is the solution for (dy)/(dx)=xe^{5y-3x},y(0)=1 ?

The solution for (dy)/(dx)=xe^{5y-3x},y(0)=1 is y=-(ln((5e^{-3x}x)/3+5/9 e^{-3x}+1/(e^5)-5/9))/(5)

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(dy)/(dx)=xe^{5y-3x},y(0)=1

\frac{d y}{d x} = x e^{5 y - 3 x}, y (0) = 1

y = - \frac{ln ( \frac{5 e ^{- 3 x} x}{3} + \frac{5}{9} e ^{- 3 x} + \frac{1}{e ^{5}} - \frac{5}{9} )}{5}

Solution steps

\frac{d y}{d x} = x e^{5 y - 3 x}

Solve separable ODE:

y = - \frac{ln ( \frac{5 e ^{- 3 x} x}{3} + \frac{5}{9} e ^{- 3 x} + \frac{1}{e ^{5}} - \frac{5}{9} )}{5}

y = - \frac{ln ( \frac{5 e ^{- 3 x} x}{3} + \frac{5}{9} e ^{- 3 x} + \frac{1}{e ^{5}} - \frac{5}{9} )}{5}

(x^{2} + 1) \frac{d y}{d x} + 4 x y = x, y (2) = 1

y^{^{'}} = x^{6} y^{- 7}

2 x sin (3 y) d x + 3 x^{2} cos (3 y) d y = 0

y^{^{'}} = - 4^{x + y}

(x sin (y)) \frac{d y}{d x} = 1 + 2 x^{2}

What is the solution for (dy)/(dx)=xe^{5y-3x},y(0)=1 ?
The solution for (dy)/(dx)=xe^{5y-3x},y(0)=1 is y=-(ln((5e^{-3x}x)/3+5/9 e^{-3x}+1/(e^5)-5/9))/(5)