What is the solution for 2cos(y^2)dx-xysin(y^2)dy=0 ?

The solution for 2cos(y^2)dx-xysin(y^2)dy=0 is

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2cos(y^2)dx-xysin(y^2)dy=0

2 cos (y^{2}) d x - x y sin (y^{2}) d y = 0

y = arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn

Solution steps

2 cos (y^{2}) d x - x y sin (y^{2}) d y = 0

Solve separable ODE:

y = arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn

y = arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn, y = - - arccos (\frac{c _{1}}{x ^{4}}) + 2 πn

\frac{d y}{d x} - e^{x - y} = 0

y d x - x d y = 0

\frac{d y}{d x} + \frac{1 - y ^{2}}{1 - x ^{2}} = 0

\frac{d y}{d x} y^{5} = x^{6}

2 x y (y^{^{'}}) = 3

What is the solution for 2cos(y^2)dx-xysin(y^2)dy=0 ?
The solution for 2cos(y^2)dx-xysin(y^2)dy=0 is