What is the solution for (dy)/(dx)=((9+18x))/(xy^2),y(1)=6 ?

The solution for (dy)/(dx)=((9+18x))/(xy^2),y(1)=6 is y=3\sqrt[3]{ln(x)+2x+6}

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(dy)/(dx)=((9+18x))/(xy^2),y(1)=6

\frac{d y}{d x} = \frac{( 9 + 18 x )}{x y ^{2}}, y (1) = 6

y = 3 3 ln (x) + 2 x + 6

Solution steps

\frac{d y}{d x} = \frac{( 9 + 18 x )}{x y ^{2}}

Solve separable ODE:

y = 3 3 ln (x) + 2 x + 6

y = 3 3 ln (x) + 2 x + 6

\frac{d y}{d x} y = (x + 7) (2 x + 9)

y^{^{'}} (p) = \frac{1}{9} y (p) (2 y (p) - 1) (p - 3)

2 y y^{^{'}} = 15 t^{2}, y (0) = 6

\frac{d y}{d x} + \frac{d y}{d x} + y = 0

\frac{d y}{d x} x \cdot cos (y) = 1

What is the solution for (dy)/(dx)=((9+18x))/(xy^2),y(1)=6 ?
The solution for (dy)/(dx)=((9+18x))/(xy^2),y(1)=6 is y=3\sqrt[3]{ln(x)+2x+6}