What is the solution for (dy)/(dx)(1+x^4)-3x^3y=0,y(1)=2 ?

The solution for (dy)/(dx)(1+x^4)-3x^3y=0,y(1)=2 is y=(2(1+x^4)^{3/4}}{e^{\frac{3ln(2))/4}}

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(dy)/(dx)(1+x^4)-3x^3y=0,y(1)=2

\frac{d y}{d x} (1 + x^{4}) - 3 x^{3} y = 0, y (1) = 2

y = \frac{2 ( 1 + x ^{4} ) ^{\frac{3}{4}}}{e ^{\frac{3 l n ( 2 )}{4}}}

Solution steps

\frac{d y}{d x} (1 + x^{4}) - 3 x^{3} y = 0

Solve separable ODE:

y = \frac{2 ( 1 + x ^{4} ) ^{\frac{3}{4}}}{e ^{\frac{3 l n ( 2 )}{4}}}

y = \frac{2 ( 1 + x ^{4} ) ^{\frac{3}{4}}}{e ^{\frac{3 l n ( 2 )}{4}}}

y^{2} \frac{d y}{d x} = x

\frac{d}{d x} (2 y \cdot ln (y)) = \frac{d x}{d x}

\frac{d x}{d t} = \frac{x}{2 t}

x y^{^{'}} = y - y^{2}, y (1) = 2

y^{^{'}} = \frac{x - 3}{y + 4}

What is the solution for (dy)/(dx)(1+x^4)-3x^3y=0,y(1)=2 ?
The solution for (dy)/(dx)(1+x^4)-3x^3y=0,y(1)=2 is y=(2(1+x^4)^{3/4}}{e^{\frac{3ln(2))/4}}