What is the (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 ?

The (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 is x^3

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(dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1

\frac{d y}{d x} = \frac{x ^{3}}{( y + 2 ) ^{2}}, y (0) = - 1

x^{3}

Solution steps

\frac{x ^{3}}{( y + 2 ) ^{2}} = \frac{x ^{3}}{( y + 2 ) ^{2}}

Constant function results in a constant

y (0) = - 1

= \frac{x ^{3}}{( - 1 + 2 ) ^{2}}

Expand

\frac{x ^{3}}{( - 1 + 2 ) ^{2}} : x^{3}

= x^{3}

x^{^{'}} = 4 + 2 x

\frac{d y}{d x} = - k (y - 70), y (0) = 205

(1 + x^{2}) y^{^{'}} - x y = x y^{2}

\frac{d h}{d t} = 2 h

(x + x) \frac{d y}{d x} = y + y

What is the (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 ?
The (dy)/(dx)=(x^3)/((y+2)^2),y(0)=-1 is x^3