What is laplacetransform e^{6-2t} ?

The answer to laplacetransform e^{6-2t} is (e^6)/(s+2)

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laplacetransform e^{6-2t}

laplace transform

e^{6 - 2 t}

\frac{e ^{6}}{s + 2}

Solution steps

L {e^{6 - 2 t}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= e^{6} L {e^{- 2 t}}

L {e^{- 2 t}} : \frac{1}{s + 2}

= e^{6} \frac{1}{s + 2}

Refine

e^{6} \frac{1}{s + 2} : \frac{e ^{6}}{s + 2}

= \frac{e ^{6}}{s + 2}

\int_{0}^{1} x^{3} (2 x^{4} + 3)^{2} d x

\frac{10}{2 s + 1}

\int \frac{( x + 5 )}{( x ^{2} + 16 )} d x

\int \frac{1}{x ^{3}} d x

x^{2} y^{^{''}} - 3 x y^{^{'}} + 3 y = 0

What is laplacetransform e^{6-2t} ?
The answer to laplacetransform e^{6-2t} is (e^6)/(s+2)