What is the solution for (dy)/(dx)=(x-1)(y+1) ?

The solution for (dy)/(dx)=(x-1)(y+1) is y=e^{(x^2)/2-x+c_{1}}-1

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(dy)/(dx)=(x-1)(y+1)

\frac{d y}{d x} = (x - 1) (y + 1)

y = e^{\frac{x ^{2}}{2} - x + c_{1}} - 1

Solution steps

\frac{d y}{d x} = (x - 1) (y + 1)

Solve separable ODE:

y = e^{\frac{x ^{2}}{2} - x + c_{1}} - 1

y = e^{\frac{x ^{2}}{2} - x + c_{1}} - 1

t^{2} y + 11 t y^{^{'}} - 11 y = 0, y^{1} (0) = t

\frac{d P}{d t} = 2 P - \frac{P ^{2}}{2}

\frac{d y}{d x} = (x - 1) (y + 2)

y^{^{'}} = \frac{x y}{1 + x ^{2}}

(x^{2} + 9) u^{^{'}} + 2 x H (x) = 0

What is the solution for (dy)/(dx)=(x-1)(y+1) ?
The solution for (dy)/(dx)=(x-1)(y+1) is y=e^{(x^2)/2-x+c_{1}}-1