What is the solution for (x+x/y)dx-dy=0 ?

The solution for (x+x/y)dx-dy=0 is y=-\W(-1/(e^{(-c_{1)+x^2)/2}})-1

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(x+x/y)dx-dy=0

(x + \frac{x}{y}) d x - d y = 0

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

Solution steps

(x + \frac{x}{y}) d x - d y = 0

Solve separable ODE:

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

y = - W (- \frac{1}{e ^{\frac{- c _{1} + x ^{2}}{2}}}) - 1

\frac{d y}{d x} y = sin^{3} (cos (9 x))

\frac{d y}{d t} 400 = - \frac{π}{9} \cdot 8 y

\frac{d y}{d x} = 85 y x^{16}, y = 4

\frac{1}{x} \frac{d y}{d x} = 2 - 4 y

x^{^{'}} = x - t x - t + 1

What is the solution for (x+x/y)dx-dy=0 ?
The solution for (x+x/y)dx-dy=0 is y=-\W(-1/(e^{(-c_{1)+x^2)/2}})-1