What is the solution for 5x(y^2+7)dx-ydy=0 ?

The solution for 5x(y^2+7)dx-ydy=0 is y=sqrt(e^{5x^2+c_{1)}-7},y=-sqrt(e^{5x^2+c_{1)}-7}

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5x(y^2+7)dx-ydy=0

5 x (y^{2} + 7) d x - y d y = 0

y = e^{5 x^{2} + c_{1}} - 7, y = - e^{5 x^{2} + c_{1}} - 7

Solution steps

5 x (y^{2} + 7) d x - y d y = 0

Solve separable ODE:

y = e^{5 x^{2} + c_{1}} - 7, y = - e^{5 x^{2} + c_{1}} - 7

y = e^{5 x^{2} + c_{1}} - 7, y = - e^{5 x^{2} + c_{1}} - 7

\frac{d S}{d t} = 0.05 - 0.00375 \cdot S, S (0) = 0

\frac{d}{d x} (2 y ln (y)) = \frac{d x}{d x}

\frac{d y}{d x} = x^{2} y^{5}

\frac{d}{d θ} (ln (y (θ))) = \frac{θ - 3}{θ cos ( θ )}

y^{^{'}} - 2 y = 3

What is the solution for 5x(y^2+7)dx-ydy=0 ?
The solution for 5x(y^2+7)dx-ydy=0 is y=sqrt(e^{5x^2+c_{1)}-7},y=-sqrt(e^{5x^2+c_{1)}-7}