What is the solution for (dy)/(dx)=(x^3y^4) ?

The solution for (dy)/(dx)=(x^3y^4) is y=-\sqrt[3]{4/(3(x^4+c_{1))}}

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(dy)/(dx)=(x^3y^4)

\frac{d y}{d x} = (x^{3} y^{4})

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

Solution steps

\frac{d y}{d x} = (x^{3} y^{4})

Solve separable ODE:

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

4 x y^{2} d y = 2 y^{3} + 2 y d x

y^{2} d y = cos (5 x) d x

\frac{d y}{d t} = 0.06 y + 3000, y (0) = 30000

\frac{d x}{d t} = 100 - \frac{x}{100}, x (0) = 2000

\frac{d y}{d x} = \frac{x ^{3}}{( y + 1 )}

What is the solution for (dy)/(dx)=(x^3y^4) ?
The solution for (dy)/(dx)=(x^3y^4) is y=-\sqrt[3]{4/(3(x^4+c_{1))}}