What is the solution for x^2dy=-(x^2-1)y^3dx ?

The solution for x^2dy=-(x^2-1)y^3dx is y=sqrt(-x/(2(-x^2-1+c_{1)x))},y=-sqrt(-x/(2(-x^2-1+c_{1)x))}

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x^2dy=-(x^2-1)y^3dx

x^{2} d y = - (x^{2} - 1) y^{3} d x

y = - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}, y = - - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}

Solution steps

x^{2} d y = - (x^{2} - 1) y^{3} d x

Solve separable ODE:

y = - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}, y = - - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}

y = - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}, y = - - \frac{x}{2 ( - x ^{2} - 1 + c _{1} x )}

2 y y^{^{'}} = 18 t^{2}, y (0) = 5

6 y^{^{'}} + 5 y = 0

\frac{d y}{d x} sin (y) = (6 x^{4} - 6)

d y - (y - 3) 2 d x = 0

x y^{^{'}} - 2 y + 4 = 0

What is the solution for x^2dy=-(x^2-1)y^3dx ?
The solution for x^2dy=-(x^2-1)y^3dx is y=sqrt(-x/(2(-x^2-1+c_{1)x))},y=-sqrt(-x/(2(-x^2-1+c_{1)x))}