What is the solution for (df)/(dt)=-0.01*f(t)^{(1.84)} ?

The solution for (df)/(dt)=-0.01*f(t)^{(1.84)} is f(t)=e^{-0.00352…t^{2.84}+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(df)/(dt)=-0.01*f(t)^{(1.84)}

\frac{df}{d t} = - 0.01 \cdot f (t)^{(1.84)}

f (t) = e^{- 0.00352 \dots t^{2.84} + c_{1}}

Solution steps

\frac{df}{d t} = - 0.01 \cdot f t^{(1.84)}

Solve separable ODE:

f (t) = e^{- 0.00352 \dots t^{2.84} + c_{1}}

f (t) = e^{- 0.00352 \dots t^{2.84} + c_{1}}

x^{2} sin (y) d x - cot (y) d y = 0

\frac{d x}{d t} = 0.09 - \frac{x}{2580}

\frac{d y}{d x} + (x^{2} - 2) y = x^{2} - 2

y^{^{'}} + 9 y^{3} = 0, y (0) = y^{0}

\frac{d y}{d x} = \frac{( 3 x ^{2} - e ^{x} )}{( 2 y - 5 )}

What is the solution for (df)/(dt)=-0.01*f(t)^{(1.84)} ?
The solution for (df)/(dt)=-0.01*f(t)^{(1.84)} is f(t)=e^{-0.00352…t^{2.84}+c_{1}}