What is the solution for (dy)/(dx)+9x^2y=27x^2 ?

The solution for (dy)/(dx)+9x^2y=27x^2 is y=e^{-3x^3+c_{1}}+3

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(dy)/(dx)+9x^2y=27x^2

\frac{d y}{d x} + 9 x^{2} y = 27 x^{2}

y = e^{- 3 x^{3} + c_{1}} + 3

Solution steps

\frac{d y}{d x} + 9 x^{2} y = 27 x^{2}

Solve separable ODE:

y = e^{- 3 x^{3} + c_{1}} + 3

y = e^{- 3 x^{3} + c_{1}} + 3

\frac{d x}{d t} = 18 - \frac{18}{100} x

y^{^{'}} = - \frac{x - 2}{y - 6}, y (3) = 0

3.03 y^{^{'}} + 0.755 y = 6.05

3 (1 + x) \frac{d y}{d x} = 2 x y (y^{3} - 1)

\frac{d x}{3 sin ( y )} = \frac{4 d y}{5 sin ( x )}

What is the solution for (dy)/(dx)+9x^2y=27x^2 ?
The solution for (dy)/(dx)+9x^2y=27x^2 is y=e^{-3x^3+c_{1}}+3