What is the solution for (dy)/(dx)4x^3y^4=8 ?

The solution for (dy)/(dx)4x^3y^4=8 is y=\sqrt[5]{-5/(x^2)+c_{1}}

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(dy)/(dx)4x^3y^4=8

\frac{d y}{d x} 4 x^{3} y^{4} = 8

y = 5 - \frac{5}{x ^{2}} + c_{1}

Solution steps

\frac{d y}{d x} 4 x^{3} y^{4} = 8

Solve separable ODE:

y = 5 - \frac{5}{x ^{2}} + c_{1}

y = 5 - \frac{5}{x ^{2}} + c_{1}

\frac{d y}{d t} = - 0.17 (100 - y)

\frac{( d y )}{( d x )} = \frac{( 1 )}{( 4 ) y}

y^{^{'}} = - 2 y - 8, y (0) = 0

y^{^{'}} = - \frac{3 y}{1000 + 3 t}

\frac{d y}{d x} = \frac{1 + y ^{6}}{x y ^{5}}

What is the solution for (dy)/(dx)4x^3y^4=8 ?
The solution for (dy)/(dx)4x^3y^4=8 is y=\sqrt[5]{-5/(x^2)+c_{1}}