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Popular >

yy^'=2t^3,y(0)=2

Solution

y y^{^{'}} = 2 t^{3}, y (0) = 2

Solution

y = t^{4} + 4

Solution steps

y y^{'} (t) = 2 t^{3}

Solve separable ODE:

y = t^{4} + 4

y = t^{4} + 4

Graph

Popular Examples

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\frac{d x}{d t} = \frac{- 2 x}{30 + t}

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y^{^{'}} - x y = 2 x y^{\frac{- 1}{2}}

3y^2(x-3)(dy)/(dx)=k

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(dx)/(dy)=tan(x)

\frac{d x}{d y} = tan (x)

y^'=(e^{-x})/(sin(y)),y(0)=1

y^{^{'}} = \frac{e ^{- x}}{sin ( y )}, y (0) = 1

Frequently Asked Questions (FAQ)

What is the solution for yy^'=2t^3,y(0)=2 ?
The solution for yy^'=2t^3,y(0)=2 is y=sqrt(t^4+4)