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Popular >

f^'(t)-f(t)=2,f(0)=0

Solution

f^{^{'}} (t) - f (t) = 2, f (0) = 0

Solution

f (t) = 2 e^{t} - 2

Solution steps

f^{'} (t) - f (t) = 2

Solve separable ODE:

f (t) = 2 e^{t} - 2

f (t) = 2 e^{t} - 2

Graph

Popular Examples

y y^{^{'}} = x - x y

(dy)/(dt)=(e^t)/(2y)

\frac{d y}{d t} = \frac{e ^{t}}{2 y}

(dy)/(dx)=4y^2,ln(x)y(1)=-1

\frac{d y}{d x} = 4 y^{2}, ln (x) y (1) = - 1

y(dy)/(dx)+1/(sqrt(1-x^2))(y^2+1)=0

y \frac{d y}{d x} + \frac{1}{1 - x ^{2}} (y^{2} + 1) = 0

(dy)/(dx)=(180-x)/(4(25+y))

\frac{d y}{d x} = \frac{180 - x}{4 ( 25 + y )}

Frequently Asked Questions (FAQ)

What is the solution for f^'(t)-f(t)=2,f(0)=0 ?
The solution for f^'(t)-f(t)=2,f(0)=0 is f(t)=2e^t-2