What is the derivative of 7^{2x} ?

The derivative of 7^{2x} is 2ln(7)*49^x

What is the first derivative of 7^{2x} ?

The first derivative of 7^{2x} is 2ln(7)*49^x

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\frac{d}{d x} (7^{2 x})

2 ln (7) \cdot 4 9^{x}

Solution steps

\frac{d}{d x} (7^{2 x})

Simplify

7^{2 x} : 4 9^{x}

= \frac{d}{d x} (4 9^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 4 9^{x} ln (49)

Simplify

ln (49) : 2 ln (7)

= 2 ln (7) \cdot 4 9^{x}

\int \frac{1}{1 + y} d y

\int x 9 + x^{2} d x

y = \frac{1}{4} x^{2} - \frac{1}{2} ln (x)

n = 1 \sum \infty \frac{1}{e ^{n^{2}}}

\frac{\partial}{\partial y} (2 x e^{y})

What is the derivative of 7^{2x} ?
The derivative of 7^{2x} is 2ln(7)*49^x
What is the first derivative of 7^{2x} ?
The first derivative of 7^{2x} is 2ln(7)*49^x