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Popular >

y^'=(-xy^2)/4

Solution

y^{^{'}} = \frac{- x y ^{2}}{4}

Solution

y = - \frac{8}{- x ^{2} + c _{1}}

Solution steps

y^{'} (x) = \frac{- x y ^{2}}{4}

Solve separable ODE:

y = - \frac{8}{- x ^{2} + c _{1}}

y = - \frac{8}{- x ^{2} + c _{1}}

Graph

Popular Examples

(dx)/(dy)=60-x/(100),x=4000,y=0

\frac{d x}{d y} = 60 - \frac{x}{100}, x = 4000, y = 0

e^y(dy)/(dx)-x^2=0,y(0)=0

e^{y} \frac{d y}{d x} - x^{2} = 0, y (0) = 0

(dv)/(dt)=60-9/100*v

\frac{d v}{d t} = 60 - \frac{9}{100} \cdot v

e^yy^'=((ln(t))^2)/t ,y(1)=ln(8)

e^{y} y^{^{'}} = \frac{( ln ( t ) ) ^{2}}{t}, y (1) = ln (8)

y^{^{'}} = - (x + 2) y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'=(-xy^2)/4 ?
The solution for y^'=(-xy^2)/4 is y=-8/(-x^2+c_{1)}