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Popular >

y^'=1-y/(10)

Solution

y^{^{'}} = 1 - \frac{y}{10}

Solution

y = - e^{\frac{- t - c _{1}}{10}} + 10

Solution steps

y^{'} (t) = 1 - \frac{y}{10}

Solve separable ODE:

y = - e^{\frac{- t - c _{1}}{10}} + 10

y = - e^{\frac{- t - c _{1}}{10}} + 10

Graph

Popular Examples

4(dy)/(dt)-1/2 (dy)/(dt)=a+32-4y

4 \frac{d y}{d t} - \frac{1}{2} \frac{d y}{d t} = a + 32 - 4 y

20(dy)/(dx)+y=1

20 \frac{d y}{d x} + y = 1

\frac{d x}{d y} = π \cdot x

(dy)/(dx)=0.07-y/(708)

\frac{d y}{d x} = 0.07 - \frac{y}{708}

y^'+4y+16=0,y(0)=2

y^{^{'}} + 4 y + 16 = 0, y (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=1-y/(10) ?
The solution for y^'=1-y/(10) is y=-e^{(-t-c_{1})/(10)}+10