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Popular >

2dx-e^{y-x}dy=0

Solution

2 d x - e^{y - x} d y = 0

Solution

y = ln (2 e^{x} + c_{1})

Solution steps

2 d x - e^{y - x} d y = 0

Solve separable ODE:

y = ln (2 e^{x} + c_{1})

y = ln (2 e^{x} + c_{1})

Graph

Popular Examples

y^2=x(x+2)(dy)/(dx)

y^{2} = x (x + 2) \frac{d y}{d x}

(dS)/(dt)=0.06-(3S)/(1420),t=10

\frac{d S}{d t} = 0.06 - \frac{3 S}{1420}, t = 10

(dx)/(dt)= 5/(xe^{t+4x)}

\frac{d x}{d t} = \frac{5}{x e ^{t + 4 x}}

y^{^{'}} = - 5 x^{4} y^{2}

(dy)/(dt)=ky+an

\frac{d y}{d t} = k y + an

Frequently Asked Questions (FAQ)

What is the solution for 2dx-e^{y-x}dy=0 ?
The solution for 2dx-e^{y-x}dy=0 is y=ln(2e^x+c_{1})