What is the solution for y^'(s)(-s^2-2s)-2sy(s)=0 ?

The solution for y^'(s)(-s^2-2s)-2sy(s)=0 is y(s)=(c_{1})/(s^2+4s+4)

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y^'(s)(-s^2-2s)-2sy(s)=0

y^{^{'}} (s) (- s^{2} - 2 s) - 2 sy (s) = 0

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

Solution steps

y^{'} (s) (- s^{2} - 2 s) - 2 sy (s) = 0

Solve separable ODE:

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

y (s) = \frac{c _{1}}{s ^{2} + 4 s + 4}

\frac{d y}{d x} y = (csc (x) - cot (x))^{- 1}

y^{^{'}} + 36 y = 0

4 t \frac{d y}{d t} + y = 0

\frac{( v + 1 ) d v}{v ^{2}} = \frac{- 2 d x}{x}

x y^{^{'}} = e^{(6 y + x)}

What is the solution for y^'(s)(-s^2-2s)-2sy(s)=0 ?
The solution for y^'(s)(-s^2-2s)-2sy(s)=0 is y(s)=(c_{1})/(s^2+4s+4)