What is the solution for (x+2)(dy)/(dx)=xy+3x-y-3 ?

The solution for (x+2)(dy)/(dx)=xy+3x-y-3 is y=(e^{x+c_{1}})/(x^3+6x^2+12x+8)-3

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(x+2)(dy)/(dx)=xy+3x-y-3

(x + 2) \frac{d y}{d x} = x y + 3 x - y - 3

y = \frac{e ^{x + c_{1}}}{x ^{3} + 6 x ^{2} + 12 x + 8} - 3

Solution steps

(x + 2) \frac{d y}{d x} = x y + 3 x - y - 3

Solve separable ODE:

y = \frac{e ^{x + c_{1}}}{x ^{3} + 6 x ^{2} + 12 x + 8} - 3

y = \frac{e ^{x + c_{1}}}{x ^{3} + 6 x ^{2} + 12 x + 8} - 3

cos (y) y^{^{'}} = sin^{2} (x) cos (x), y (0) = \frac{π}{6}

2 \frac{d y}{d x} + x y = 2 x

y^{^{'}} = 4 x y^{6}

y^{^{'}} = ab - \frac{y}{c} b

\frac{d y}{d x} = \frac{x x ^{2} + 3}{e ^{2 y}}

What is the solution for (x+2)(dy)/(dx)=xy+3x-y-3 ?
The solution for (x+2)(dy)/(dx)=xy+3x-y-3 is y=(e^{x+c_{1}})/(x^3+6x^2+12x+8)-3