What is the solution for (dy)/(dx)=x^3(y-2),y(0)=4 ?

The solution for (dy)/(dx)=x^3(y-2),y(0)=4 is y=2e^{(x^4)/4}+2

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(dy)/(dx)=x^3(y-2),y(0)=4

\frac{d y}{d x} = x^{3} (y - 2), y (0) = 4

y = 2 e^{\frac{x ^{4}}{4}} + 2

Solution steps

\frac{d y}{d x} = x^{3} (y - 2)

Solve separable ODE:

y = 2 e^{\frac{x ^{4}}{4}} + 2

y = 2 e^{\frac{x ^{4}}{4}} + 2

y^{^{'}} = y cos (x), y (0) = 5

y^{^{'}} = 6 x y + 42 x - 4 y - 28

x^{2} y^{^{'}} - 6 x y + 10 y = 0

y^{^{'}} = - \frac{x - 7}{49 y - 343}, y (8) = 0

\frac{d t}{d y} = e^{6 t + 3 y}, y (0) = 16

What is the solution for (dy)/(dx)=x^3(y-2),y(0)=4 ?
The solution for (dy)/(dx)=x^3(y-2),y(0)=4 is y=2e^{(x^4)/4}+2