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Popular >

y^'=4xy^4

Solution

y^{^{'}} = 4 x y^{4}

Solution

y = - \frac{1}{3 3 ( 2 x ^{2} + c _{1} )}

Solution steps

y^{'} (x) = 4 x y^{4}

Solve separable ODE:

y = - \frac{1}{3 3 ( 2 x ^{2} + c _{1} )}

y = - \frac{1}{3 3 ( 2 x ^{2} + c _{1} )}

Graph

Popular Examples

(2+x^{10})(dy}{dx}=\frac{x^9)/y

(2 + x^{10}) \frac{d y}{d x} = \frac{x ^{9}}{y}

(dy)/(dx)y=(x^2-7)(x^3+4x+2)

\frac{d y}{d x} y = (x^{2} - 7) (x^{3} + 4 x + 2)

y^{^{'}} + 7 x ey = 0

(x^2}{y^2-1}y^'=\frac{3x^3)/y ,y(0)=2

\frac{x ^{2}}{y ^{2} - 1} y^{^{'}} = \frac{3 x ^{3}}{y}, y (0) = 2

(dy)/(dx)=110yx^{10},y(0)=2

\frac{d y}{d x} = 110 y x^{10}, y (0) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=4xy^4 ?
The solution for y^'=4xy^4 is y=-1/(\sqrt[3]{3(2x^2+c_{1))}}