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Popular >

2t(dy)+y^2(dt)=0

Solution

2 t (d y) + y^{2} (d t) = 0

Solution

y = - \frac{2}{- ln ( t ) + c _{1}}

Solution steps

2 t (d y) + y^{2} (d t) = 0

Solve separable ODE:

y = - \frac{2}{- ln ( t ) + c _{1}}

y = - \frac{2}{- ln ( t ) + c _{1}}

Graph

Popular Examples

(dx)/(dt)=-x/(924)

\frac{d x}{d t} = - \frac{x}{924}

(dy)/(dx)=(10+19x)/(xy^2)

\frac{d y}{d x} = \frac{10 + 19 x}{x y ^{2}}

(dy)/(dx)=((2x+3))/((2y-2))

\frac{d y}{d x} = \frac{( 2 x + 3 )}{( 2 y - 2 )}

(dy)/(dx)=((xsqrt(x^2+1)))/(ye^y)

\frac{d y}{d x} = \frac{( x x ^{2} + 1 )}{y e ^{y}}

y^'=(xe^{x+y})/y

y^{^{'}} = \frac{x e ^{x + y}}{y}

Frequently Asked Questions (FAQ)

What is the solution for 2t(dy)+y^2(dt)=0 ?
The solution for 2t(dy)+y^2(dt)=0 is y=-2/(-ln(t)+c_{1)}