What is the solution for (dy)/(dx)=(y(1-y)) ?

The solution for (dy)/(dx)=(y(1-y)) is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}

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(dy)/(dx)=(y(1-y))

\frac{d y}{d x} = (y (1 - y))

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

Solution steps

\frac{d y}{d x} = (y (1 - y))

Solve separable ODE:

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

y = - \frac{e ^{x + c_{1}}}{1 - e ^{x + c_{1}}}

(t^{2} - 6 t + 5) y^{^{'}} = y

\frac{f ^{^{'}} ( x )}{f ( x )} = x e^{x}, f (0) = 4

y^{^{'}} = \frac{3 y ^{2} + 9}{( 2 x y )}

y^{^{'}} + 5 x y = x

\frac{d y}{d x} = \frac{( ln ( x ) ) ^{6}}{x y ^{2}}, y (1) = 4

What is the solution for (dy)/(dx)=(y(1-y)) ?
The solution for (dy)/(dx)=(y(1-y)) is y=-(e^{x+c_{1}})/(1-e^{x+c_{1)}}