What is the solution for y^'+xy=5xy^2 ?

The solution for y^'+xy=5xy^2 is y= 1/(5(1-e^{\frac{x^2){2}+c_{1}})}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+xy=5xy^2

y^{^{'}} + x y = 5 x y^{2}

y = \frac{1}{5 ( 1 - e ^{\frac{x ^{2}}{2} + c_{1}} )}

Solution steps

y^{'} (x) + x y = 5 x y^{2}

Solve separable ODE:

y = \frac{1}{5 ( 1 - e ^{\frac{x ^{2}}{2} + c_{1}} )}

y = \frac{1}{5 ( 1 - e ^{\frac{x ^{2}}{2} + c_{1}} )}

\frac{x}{y} = \frac{d y}{d x}

y^{^{'}} = e^{y}, y (0) = 0

2 x^{3} H (x) (x)^{2} d x + x^{4} H (x) d H (x) = 0

(1 + x^{2}) \cdot y^{^{'}} = x (1 - y)

\frac{d y}{d x} - 2 x y = 4 x, y (0) = 3

What is the solution for y^'+xy=5xy^2 ?
The solution for y^'+xy=5xy^2 is y= 1/(5(1-e^{\frac{x^2){2}+c_{1}})}